HackerRank Migratory Birds Problem Solution in C
#include <math.h>
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#include <assert.h>
#include <limits.h>
#include <stdbool.h>
int main(){
    int n; 
    scanf("%d",&n);
    int *types = malloc(sizeof(int) * n);
    for(int types_i = 0; types_i < n; types_i++){
       scanf("%d",&types[types_i]);
    }
    int c[5] = {0};
    for (int i=0; i<n; i++){
        c[types[i]-1]++;
    }
    int max = -1;
    int maxi = -1;
    for (int i=0; i<5; i++) {
        if(c[i]>max){
            max = c[i];
            maxi = i;
        }
    }
    printf("%d\n", maxi+1);
   
    // your code goes here
    return 0; }
HackerRank Migratory Birds Problem Solution  in JavaScript
process.stdin.resume();
process.stdin.setEncoding('ascii');
var input_stdin = "";
var input_stdin_array = "";
var input_currentline = 0;
process.stdin.on('data', function (data) {
    input_stdin += data;
});
process.stdin.on('end', function () {
    input_stdin_array = input_stdin.split("\n");
    main();    
});
function readLine() {
    return input_stdin_array[input_currentline++];
}
/////////////// ignore above this line ////////////////////
function main() {
    var n = parseInt(readLine()),
    types = readLine().split(' ');
    types = types.map(Number);
    // your code goes here
    var occ = [0,0,0,0,0],
        max_occ = 0,
        ans = 0
    for (var i = 0 ; i < types.length ; i++) occ[types[i]-1]++
    for (var i = 0 ; i < 5 ; i++) if (occ[i] > max_occ) max_occ = occ[i], ans = i
    
    //console.error(occ)
    console.log(ans + 1)
}HackerRank Migratory Birds Problem Solution in Python
#!/bin/python3
import sys
n = int(input().strip())
types = list(map(int, input().strip().split(' ')))
# your code goes here
counter = [0 for ii in range(5)]
for t in types:
    counter[t-1] += 1
hf = 0
for nth, c in enumerate(counter[1:], start=1):
    if c > counter[hf]:
        hf = nth
print(hf+1) 
 
 
 
HackerRank Time Conversion Problem Solution in C#include <stdio.h>
#include <string.h>
#include <math.h>
#include <stdlib.h>
int main() {
    /* Enter your code here. Read input from STDIN. Print output to STDOUT */    
       char time[10];
    int hr1,hr2,hr3,hr,min,sec,i;
    scanf("%s",time);
    if(time[8]=='A')
    {
        if(time[0]=='1'&&time[1]=='2')
            {
            time[0]='0';
            time[1]='0';
        }
        for(i=0;i<8;i++)
                    printf("%c",time[i]);
    }
    else if(time[8]=='P')
        {
            hr1=time[0]-'0';
            hr2=time[1]-'0';
            hr3=hr1*10+hr2;
            hr=12+hr3;
        if(hr==24)
            hr=12;
            printf("%d",hr);
        for(i=2;i<8;i++)
            printf("%c",time[i]);
    }
    return 0;
}
HackerRank Time Conversion Problem Solution in JavaScript
function processData(input) {
    //Enter your code here
    if(input.indexOf('PM') !== -1) {
        input = input.replace('PM', '');
        var data = input.split(':');
        var hour = parseInt(data[0], 10);
        if(hour !== 12) {
            hour += 12;
        }
        
        data[0] = hour;
        
        console.log(data.join(':'));
        
    } else {
        input = input.replace('AM', '');
        var data = input.split(':');
        var hour = parseInt(data[0], 10);
        if(hour === 12) {
            hour = 0;
        }
        
        data[0] = hour < 10 ? '0' + hour : hour;
        console.log(data.join(':'));
    }
} 
process.stdin.resume();
process.stdin.setEncoding("ascii");
_input = "";
process.stdin.on("data", function (input) {
    _input += input;
});
process.stdin.on("end", function () {
   processData(_input);
});
HackerRank Time Conversion Problem Solution in Python
inS = input()
if (inS[0:2] == '12'):
    if (inS[8:] == 'AM'):
        hrs = int(inS[0:2])
        hrs = hrs - 12
        hrs = str(hrs) + '0'
        outS = hrs + inS[2:8]
        print(outS)
    else:
        print(inS[0:8])
elif (inS == '12:00:00PM'):
    print('12:00:00')
elif (inS[8:] == 'AM'):
    print(inS[0:8])
else:
    hrs = int(inS[0:2])
    hrs = hrs + 12
    outS = str(hrs) + inS[2:8]
    print(outS)