#include <stdio.h>
#include <string.h>
#include <math.h>
#include <stdlib.h>

int main() {
    float a,b,c,p=0.0,n=0.0,z=0.0;
   int num;
    scanf("%d",&num);
    int arr[num];
    for(int i=0;i<num;i++)
        scanf("%d",&arr[i]);
    
    for(int q=0;q<num;q++)
        {
        if(arr[q]==0)
        {z=z+1.0;}
        if(arr[q]>0)
        {p=p+1.0;}
        if(arr[q]<0)
        {n=n+1.0;}
    }
    
    printf("%.3f\n",p/((double)num));
     printf("%.3f\n",n/((double)num));
             printf("%.3f\n",z/((double)num));
    /* Enter your code here. Read input from STDIN. Print output to STDOUT */    
    return 0;
}

Hackerrank Plus Minus Problem Solution in JavaScript

function processData(input) {
  var lines = input.split('\n');
  var N = lines[0];
  var numbers = lines[1].split(' ').map(function(el) {
    return parseInt(el, 10)
  });
  
  var pos = numbers.filter(function(el) {
    return el > 0;
  }).length;
  
  var neg = numbers.filter(function(el) {
    return el < 0;
  }).length;
  
  var zero = N - pos - neg;
  
  console.log(pos / N);
  console.log(neg / N);
  console.log(zero / N);
} 

process.stdin.resume();
process.stdin.setEncoding("ascii");
_input = "";
process.stdin.on("data", function (input) {
    _input += input;
});

process.stdin.on("end", function () {
   processData(_input);
});

Hackerrank Plus Minus Problem Solution in Python

import sys

N = 0
p = 0
m = 0
z = 0
for line in sys.stdin:
    if(N == 0):
        N = int(line)
    else:
        myList = line.split()
        
        for val in myList:
            if int(val) < 0:
                m += 1
            elif int(val) > 0:
                p += 1
            else:
                z += 1
#print '%d %d %d' %(p,m,z)            
print '%f' %((p / float(N)))
print '%f' %((m / float(N)))
print '%f' %((z / float(N)))