Hackerrank Grading Students Problem Solution

#include <stdio.h>

int main(void) {
	// your code goes here
	int t,n,i,ans;
	scanf("%d",&t);
	for(i=1;i<=t;i++)
	{
	    scanf("%d",&n);
	    if(n<38 || n%5==0 || n%5==1 || n%5==2)
	    {
	        printf("%d\n",n);
	    }
	    else if(n%5==3)
	    {
	        ans=n+2;
	        printf("%d\n",ans);
	    }
	    else if(n%5==4)
	    {
	        ans=n+1;
	        printf("%d\n",ans);
	    }
	}
	return 0;
}

Hackerrank Grading Students Problem Solution in JavaScript

process.stdin.resume();
process.stdin.setEncoding('ascii');

var input_stdin = "";
var input_stdin_array = "";
var input_currentline = 0;

process.stdin.on('data', function (data) {
    input_stdin += data;
});

process.stdin.on('end', function () {
    input_stdin_array = input_stdin.split("\n");
    main();    
});

function readLine() {
    return input_stdin_array[input_currentline++];
}

/////////////// ignore above this line ////////////////////

function main() {
    var n = parseInt(readLine());
    for(var a0 = 0; a0 < n; a0++){
        var grade = parseInt(readLine());
        
        if(grade >= 38){
            var closest = Math.ceil(grade / 5) * 5;
            var diff = closest - grade;
            
            if(diff < 3){
                grade = closest;
            }
        }

        console.log(grade);
    }

}

Hackerrank Grading Students Problem Solution in Python

#!/bin/python3

import sys


n = int(input().strip())
for a0 in range(n):
    grade = int(input().strip())
    if grade > 37:
        if grade % 5 > 2:
            grade = grade + 5 - grade % 5
    print (grade)